
Go backward to Solution to part (d)
Go up to 3 Variable Elimination Algorithm (Singly Connected)
Go forward to Solution to part (f)
Solution to part (e)
Suppose we now eliminate C. What factor(s) are removed, and what
factor is created?
The factors that contain C are f2(B,C) and f4(C). We thus
create a factor f5(B), defined by:
B | Value |
true | 0.3972 * 0.645 + 0.6028 * 0.365 = 0.476216 |
false | 0.7964 * 0.645 + 0.2036 * 0.365 = 0.587992
|
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material, ©David Poole, Alan Mackworth and Randy Goebel, 1999
