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Solution :

`BC` is diameter=> `r= (BC)/2= 14/2 = 7`cm <br>
area(shaded) = ar(square) - `2*area(BPC)` <br>
= ar(square)-area(circle) <br>
`=(14)^2- pi*7^2 cm^2`<br>
`= (14^2 - 22/7*7*7)cm^2` <br>
`=(196-154) = 42cm^2` <br>
answer**What we already learned in previous classes**

**Perimeter and Area of a circle**

**Area enclosed by two concentric circles**

**Some Useful Results**

**Minor and major sector**

**Area of a sector**

**Find the area of a sector whose radius is 14 cm and angle of sector is `45^@`.**

**Some important points related to clock**

**Major and Minor segment**

**Area of a segment**