|\^/|     Maple 18 (APPLE UNIVERSAL OSX)
._|\|   |/|_. Copyright (c) Maplesoft, a division of Waterloo Maple Inc. 2014
 \  MAPLE  /  All rights reserved. Maple is a trademark of
 <____ ____>  Waterloo Maple Inc.
      |       Type ? for help.
> read `first_game`;
eqns := {w1 = const - p1 - p2, w2 = 11 p1 + 7 p2 - vv, w3 = 8 p1 + 14 p2 - vv,

    zz = vv}

First dictionary:  nice_solve( eqns, [zz,w1,w2,w3], [p1,p2,vv] )

Dictionary: basic = [zz, w1, w2, w3], non-basic = [p1, p2, vv]

			 zz = 
                                      vv

			 w1 = 
                                const - p1 - p2

			 w2 = 
                               11 p1 + 7 p2 - vv

			 w3 = 
                               8 p1 + 14 p2 - vv



Second dictionary:  nice_solve( eqns, [zz,w1,vv,w3], [p1,p2,w2] )

Dictionary: basic = [zz, w1, vv, w3], non-basic = [p1, p2, w2]

			 zz = 
                               11 p1 + 7 p2 - w2

			 w1 = 
                                const - p1 - p2

			 vv = 
                               11 p1 + 7 p2 - w2

			 w3 = 
                               -3 p1 + 7 p2 + w2



Third dictionary:  nice_solve( eqns, [zz,w1,p1,w3], [vv,p2,w2] )

Dictionary: basic = [zz, w1, p1, w3], non-basic = [vv, p2, w2]

			 zz = 
                                      vv

			 w1 = 
                                   vv    4 p2    w2
                          const - ---- - ---- - ----
                                   11     11     11

			 p1 = 
                               vv    7 p2    w2
                              ---- - ---- + ----
                               11     11     11

			 w3 = 
                               3 vv   98 p2   8 w2
                             - ---- + ----- + ----
                                11     11      11



Fouth dictionary:  nice_solve( eqns, [zz,w1,p1,vv], [w3,p2,w2] )

Dictionary: basic = [zz, w1, p1, vv], non-basic = [w3, p2, w2]

			 zz = 
                              11 w3   98 p2   8 w2
                            - ----- + ----- + ----
                                3       3      3

			 w1 = 
                                   w3    10 p2    w2
                          const + ---- - ----- - ----
                                   3       3      3

			 p1 = 
                                w3    7 p2    w2
                             - ---- + ---- + ----
                                3      3      3

			 vv = 
                              11 w3   98 p2   8 w2
                            - ----- + ----- + ----
                                3       3      3



Fifth dictionary:  nice_solve( eqns, [zz,p2,p1,vv], [w3,w1,w2] )

Dictionary: basic = [zz, p2, p1, vv], non-basic = [w3, w1, w2]

			 zz = 
                        49 const   2 w3   49 w1   3 w2
                        -------- - ---- - ----- - ----
                           5        5       5      5

			 p2 = 
                         3 const    w3    3 w1    w2
                         ------- + ---- - ---- - ----
                           10       10     10     10

			 p1 = 
                         7 const    w3    7 w1    w2
                         ------- - ---- - ---- + ----
                           10       10     10     10

			 vv = 
                        49 const   2 w3   49 w1   3 w2
                        -------- - ---- - ----- - ----
                           5        5       5      5