
Go backward to Solution to part (a)
Go up to 3 Variable Elimination Algorithm (Singly Connected)
Go forward to Solution to part (c)
Solution to part (b)
Suppose we were to eliminate D. What factor(s) are removed and
which factor is created. Give the table for the created
factor.
We remove the factors containing D, these are f1(D) and
P(C|B,D). We create a new factor f2(B,C) on the remaining
factors.
B | C | Value |
true | true | 0.93 * 0.112 + 0.33 * 0.888 = 0.3972 |
true | false | 0.07 * 0.112 + 0.67 * 0.888 = 0.6028 |
false | true | 0.53 * 0.112 + 0.83 * 0.888 = 0.7964 |
false | false | 0.47 * 0.112 + 0.17 * 0.888 = 0.2036
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material, ©David Poole, Alan Mackworth and Randy Goebel, 1999
